Point-slope form review | Linear equations | Algebra (article) | Khan Academy (2024)

Review point-slope form and how to use it to solve problems.

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  • Simmy :)

    6 years agoPosted 6 years ago. Direct link to Simmy :)'s post “In school I learned it as...”

    In school I learned it as y-y1=m(x-x1). Is it this just another way to write the same thing? Thank you

    (43 votes)

    • Kim Seidel

      6 years agoPosted 6 years ago. Direct link to Kim Seidel's post “Yes, it is essentially th...”

      Point-slope form review | Linear equations | Algebra (article) | Khan Academy (4)

      Point-slope form review | Linear equations | Algebra (article) | Khan Academy (5)

      Point-slope form review | Linear equations | Algebra (article) | Khan Academy (6)

      Yes, it is essentially the same. Sal is just using the variables "a" and "b" instead of X1 and Y1.

      (54 votes)

  • Natia Island

    5 years agoPosted 5 years ago. Direct link to Natia Island's post “what is the slope of the ...”

    what is the slope of the line through (1,0) and (3,8)?

    (12 votes)

    • Polina Vitić

      5 years agoPosted 5 years ago. Direct link to Polina Vitić's post “Let's use the *slope form...”

      Point-slope form review | Linear equations | Algebra (article) | Khan Academy (10)

      Point-slope form review | Linear equations | Algebra (article) | Khan Academy (11)

      Let's use the slope formula, where the slope (m) is equal to rise over run:

      m = rise / run
      = (y₂ - y₁) / (x₂ - x₁)
      = (8 - 0) / (3 - 1)
      = 8 / 2
      = 4

      m = 4, so the slope of the line through (1, 0) and (3, 8) is 4.

      Hope this helps!

  • ogeise001

    a year agoPosted a year ago. Direct link to ogeise001's post “how do you get that answe...”

    how do you get that answer for number 2

    (8 votes)

    • joshua

      a year agoPosted a year ago. Direct link to joshua's post “What do you mean for numb...”

      Point-slope form review | Linear equations | Algebra (article) | Khan Academy (15)

      Point-slope form review | Linear equations | Algebra (article) | Khan Academy (16)

      What do you mean for number 2? I guess I'll just explain both problems here.

      Write the point-slope equation of the line that passes through (7,3) whose slope is 2.

      This is pretty straightforward, since point-slope form requires you to just substitute values in order to form the equation.
      Answer: y - 3 = 2(x - 7)

      Write the point-slope equation of the line that passes through (3,5) and (7,1).

      To solve this, you need to find the slope first. Slope for line connecting (x1, y1) and (x2, y2) is
      (y1 - y2) / (x1 - x2).
      Answer: y - 5 = -(x - 3) or y - 1 = -(x - 7)

      What is the slope of the line y - 5 = -4(x - 8)?

      Since both coefficient for both x and y are 1, you don't have to consider anything complicated.

      To know which point does the line pass through, just substitute for x and y and compare L.H.S. with R.H.S.
      Answer: -4 (8, 5)

      Graph y - 7 = -3(x - 1)

      There are many ways to do this, such as setting a point and doing some calculation but I will use another way. Recall slope is equal to change of y-coordinate for every one unit change in the x-coordinate. So if the slope is -3, it means for every 1 unit increase in x-coordinate, y-coordinate will reduce by 3 unit (-3). So we just take the point provided in the equation (1, 7) and take another point (1 + 1, 7 - 3) = (2, 4)

      (34 votes)

  • bollesa

    2 years agoPosted 2 years ago. Direct link to bollesa's post “So this is basically (cha...”

    So this is basically (change in y)=(slope)(change in x)?

    (9 votes)

    • Kim Seidel

      2 years agoPosted 2 years ago. Direct link to Kim Seidel's post “Yes, good observation.”

      Point-slope form review | Linear equations | Algebra (article) | Khan Academy (20)

      Yes, good observation.

      (13 votes)

  • hannah.mcgregor

    5 years agoPosted 5 years ago. Direct link to hannah.mcgregor's post “I understand how this can...”

    I understand how this can create an equation, but not how it could be solved to an answer with two unknowns. If it can't be solved, what is the purpose exactly?
    Thanks, Lilly

    (5 votes)

    • Kim Seidel

      5 years agoPosted 5 years ago. Direct link to Kim Seidel's post “Linear equations are equa...”

      Point-slope form review | Linear equations | Algebra (article) | Khan Academy (24)

      Linear equations are equations that when graphed create a line.
      Every point on the line is a solution to the equation. Before learning how to create the equation, you should have learned about how to find solutions and graph the equation. Try reviewing the lessons are: https://www.khanacademy.org/math/algebra/x2f8bb11595b61c86:linear-equations-graphs

      Hope this helps.

      (12 votes)

  • taisiya Matev

    7 years agoPosted 7 years ago. Direct link to taisiya Matev's post “What does it mean when th...”

    What does it mean when the slope is simply - and you are trying to graph an equation?

    (5 votes)

    • Jacob Beauvais

      7 years agoPosted 7 years ago. Direct link to Jacob Beauvais's post “When the slope is . you s...”

      When the slope is . you should have to find it. You want to set up the problem like this:
      (-1,3) (-2,5)
      y-3=2(x-1) (answer)
      The 3 represents the y axis, and the -1 represents the x axis. you can interchange with the 2nd coordinate point. The 2 represents the slope. You can find the slope with slope-intercept form. Hope this helped.

      (7 votes)

  • Potato

    6 months agoPosted 6 months ago. Direct link to Potato's post “Why do we learn about poi...”

    Why do we learn about point-slope form in addition to the form y=mx+b? Seems like y=mx+b is better. What are the pros/cons of each form?

    (3 votes)

    • IsNewt

      6 months agoPosted 6 months ago. Direct link to IsNewt's post “With Point-slope form you...”

      With Point-slope form you can graph a line knowing any point and the slope. With slope-intercept form, you need the y-intercept(not just any point) to get the line. So if somebody tells you they can perform a job a a certain rate and gives you a certain moment(i.e. "after 25 minutes it will be 9 dollars") you immediately know the "graph" of the job. With slope-intercept, you would have to work to find the moment representing the y-intercept of the job's "graph".
      Hopefully this helps. Tell me if my answer was not satisfactory.

      (7 votes)

  • mcdonand001

    10 months agoPosted 10 months ago. Direct link to mcdonand001's post “What is the slope of a li...”

    What is the slope of a line that passes through the points (1,3)(1,3)left parenthesis, 1, comma, 3, right parenthesis and (7,5)(7,5)left parenthesis, 7, comma, 5, right parenthesis in the xyxyx, y-plane?

    (5 votes)

    • Kim Seidel

      10 months agoPosted 10 months ago. Direct link to Kim Seidel's post “Your post is unreadable i...”

      Your post is unreadable in its current form. It looks like you need to find the slope and you have 2 points.
      1) Label one point as (x1, y1) and the other point as (x2,y2)
      2) Then use the slope formula: m = (y2-y1)/(x2-x1). Take each values from your points and put them into the corresponding variable in the formula.
      3) Then, do the math to simplify the fraction. The result will be your slope.

      (3 votes)

  • Violeta 😾

    4 years agoPosted 4 years ago. Direct link to Violeta 😾's post “Im confused on how to fin...”

    Im confused on how to find slope. any tips anyone?

    (4 votes)

    • Ashur Hamilton

      3 years agoPosted 3 years ago. Direct link to Ashur Hamilton's post “change in y / change in x”

      change in y / change in x

      (4 votes)

  • ss1309996

    4 years agoPosted 4 years ago. Direct link to ss1309996's post “One line passes through t...”

    One line passes through the points \blueD{(-8,1)}(−8,1)start color #11accd, left parenthesis, minus, 8, comma, 1, right parenthesis, end color #11accd and \blueD{(4,4)}(4,4)start color #11accd, left parenthesis, 4, comma, 4, right parenthesis, end color #11accd. Another line passes through points \greenD{(-9,-7)}(−9,−7)start color #1fab54, left parenthesis, minus, 9, comma, minus, 7, right parenthesis, end color #1fab54 and \greenD{(9,-3)}(9,−3)start color #1fab54, left parenthesis, 9, comma, minus, 3, right parenthesis, end color #1fab54.
    Are the lines parallel, perpendicular, or neither

    (4 votes)

Point-slope form review | Linear equations | Algebra (article) | Khan Academy (2024)

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